day03-if的综合小案例
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35
day03/src/com/inmind/if01/Demo02.java
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35
day03/src/com/inmind/if01/Demo02.java
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package com.inmind.if01;
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/*
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指定考试成绩,判断学生等级
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90-100 优秀
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80-89 好
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70-79 良
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60-69 及格
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60以下 不及格
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分析:
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1.定义一个成绩变量score
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2.使用if格式三,根据不同的判断条件,输出各自学生的等级
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*/
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public class Demo02 {
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public static void main(String[] args) {
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//定义一个成绩变量score
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int score = 80;
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if (score >= 90 && score <= 100) {
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System.out.println("优秀");
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} else if (score >= 80 && score <90) {
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System.out.println("好");
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}else if(score>=70 && score<=79){
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System.out.println("良");
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}else if(score>=60 && score<=69){
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System.out.println("及格");
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}else if(score<=59&&score>=0){
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System.out.println("不及格");
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}else{//else是可以不写,要不要写要根据具体的业务题目来分析
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System.out.println("您输入的成绩有误");
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}
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System.out.println("程序结束");
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}
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}
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