进阶day06-线程安全-卖票案例的实现
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javaSE-day06/src/com/inmind/thread_safe04/Demo04.java
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javaSE-day06/src/com/inmind/thread_safe04/Demo04.java
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package com.inmind.thread_safe04;
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/*
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我们通过一个案例,演示线程的安全问题:
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电影院要卖票,我们模拟电影院的卖票过程。假设要播放的电影是 “葫芦娃大战奥特曼”,本次电影的座位共100个(本场电影只能卖100张票)。
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我们来模拟电影院的售票窗口,实现多个窗口同时卖 “葫芦娃大战奥特曼”这场电影票(多个窗口一起卖这100张票)
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需要窗口,采用线程对象来模拟;需要票,Runnable接口子类来模拟
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分析:
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一个卖100张票的任务:Runnable接口表示
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3个窗口来卖:3个线程
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*/
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public class Demo04 {
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public static void main(String[] args) {
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//创建3个窗口来执行同一个任务
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TicketTask ticketTask = new TicketTask();
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new Thread(ticketTask,"窗口1").start();
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new Thread(ticketTask,"窗口2").start();
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new Thread(ticketTask,"窗口3").start();
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}
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}
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javaSE-day06/src/com/inmind/thread_safe04/TicketTask.java
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javaSE-day06/src/com/inmind/thread_safe04/TicketTask.java
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package com.inmind.thread_safe04;
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public class TicketTask implements Runnable{
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//定义100张票电影票
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int tickeCount = 100;
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@Override
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public void run() {
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//有票就卖
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while (true) {
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if (tickeCount > 0) {
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try {
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Thread.sleep(50);
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} catch (InterruptedException e) {
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e.printStackTrace();
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}
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System.out.println(Thread.currentThread().getName() + "正在卖第" + tickeCount + "张电影票");
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tickeCount--;
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} else {
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break;
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}
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}
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}
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}
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