74 lines
1.7 KiB
Markdown
74 lines
1.7 KiB
Markdown
# 推导式
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## 推导式详细格式
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```plain
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variable = [out_exp_res for out_exp in input_list if out_exp == 2]
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out_exp_res: 列表生成元素表达式,可以是有返回值的函数。
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for out_exp in input_list: 迭代input_list将out_exp传入out_exp_res表达式中。
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if out_exp == 2: 根据条件过滤哪些值可以。
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```
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## 列表推导式
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30以内所有能被3整除的数
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```python
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multiples = [i for i in range(30) if i % 3 is 0]
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print(multiples)
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```
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30以内所有能被3整除的数的平方
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```python
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def squared(x):
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return x*x
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multiples = [squared(i) for i in range(30) if i % 3 is 0]
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print(multiples)
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```
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找到嵌套列表中名字含有两个及以上‘a’的所有名字
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```python
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fruits = [['peach','Lemon','Pear','avocado','cantaloupe','Banana','Grape'],
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['raisins','plum','apricot','nectarine','orange','papaya']]
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print([name for lst in fruits for name in lst if name.count('a') >= 2])
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```
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## 字典推导式
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将一个字典的key和value对调
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```python
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dic1 = {'a':1,'b':2}
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dic2 = {dic1[k]: k for k in dic1}
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print(dic2)
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```
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合并大小写对应的value值,将k统一成小写
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```python
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dic1 = {'a':1,'b':2,'A':4,'Y':9}
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dic2 = {k.lower():dic1.get(k.lower(),0) + dic1.get(k.upper(),0) for k in dic1.keys()}
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print(dic2)
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```
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## 集合推导式
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计算列表中每个值的平方,自带去重功能
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```python
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l = [1,2,3,4,1,-1,-2,3]
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squared = {x**2 for x in l}
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print(squared)
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```
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## 练习题
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1. 过滤掉长度小于3的字符串列表,并将剩下的转换成大写字母
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2. 求(x,y)其中x是0-5之间的偶数,y是0-5之间的奇数组成的元祖列表
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3. 将1000以内的素数放入一个列表中
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