From d0ded6780597bd35404a902415410ec6ca972347 Mon Sep 17 00:00:00 2001 From: xuxin <840198532@qq.com> Date: Tue, 15 Sep 2026 11:21:45 +0800 Subject: [PATCH] =?UTF-8?q?day02--=E6=95=B0=E6=8D=AE=E7=B1=BB=E5=9E=8B?= =?UTF-8?q?=E8=BD=AC=E6=8D=A2=5F=E5=AD=97=E7=AC=A6=E7=9A=84=E8=BD=AC?= =?UTF-8?q?=E6=8D=A2?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- day02/src/com/inmind/Demo05.java | 22 ++++++++++++++++++++++ 1 file changed, 22 insertions(+) create mode 100644 day02/src/com/inmind/Demo05.java diff --git a/day02/src/com/inmind/Demo05.java b/day02/src/com/inmind/Demo05.java new file mode 100644 index 0000000..aa9674b --- /dev/null +++ b/day02/src/com/inmind/Demo05.java @@ -0,0 +1,22 @@ +package com.inmind; +/* +数据转换--字符数据 +字符在数学运算中,是遵循ASCII码表,将对应码表中的字符对应的十进制的值参与运算 + +*/ +public class Demo05 { + public static void main(String[] args) { + //定义一个字符变量(2个字节) + char c = 'a'; + //定义一个整数int(4个字节) + int i = 10; + int sum = i + c;//此时发生了自动类型转换,char->int + System.out.println(sum);//107 + + //int强转字符char,如何操作的?? + int i1 = 111; + char c1 = (char) i1; + System.out.println(c1);//o 遵循ASCII码表,转为对应的字符 + + } +}