# Vite Development Server Arbitrary File Read Bypass (CVE-2025-30208) [中文版本(Chinese version)](README.zh-cn.md) Vite is a modern frontend build tool that provides a faster and leaner development experience for modern web projects. It consists of two major parts: a dev server with Hot Module Replacement (HMR) capability, and a build command that bundles your code with Rollup. In versions of Vite before 6.2.3, 6.1.2, 6.0.12, 5.4.15, and 4.5.10, the `server.fs.deny` feature, which is designed to restrict access to files outside of Vite's serving allow list, can be bypassed. By appending `?raw??` or `?import&raw??` to URLs using the `@fs` prefix, an attacker can read arbitrary files on the filesystem, as long as the Node.js process has permission to read them. This vulnerability occurs because trailing separators such as `?` are removed in several places during request processing, but are not accounted for in query string regular expressions, leading to the security check bypass. This vulnerability is a bypass for the patch of [CNVD-2022-44615](../CNVD-2022-44615/README.md). References: - - ## Environment Setup Execute the following command to start a Vite 6.2.2 development server: ``` docker compose up -d ``` After the server starts, you can access the Vite development environment at `http://your-ip:5173`. > Note: The development server of the old version of Vite defaults to port 3000, while the new version defaults to port 5173, please pay attention to the difference. ## Vulnerability Reproduction The vulnerability allows an attacker to read arbitrary files on the server's filesystem by bypassing the `server.fs.deny` protection. First, try to access `/etc/passwd` using the standard `@fs` prefix to verify that normal access to files outside the allowed directories is properly blocked: ![](1.png) You should receive a 403 Forbidden response because this path is outside of Vite's allowed serving list. However, by appending `?raw??` to the URL, you can bypass this restriction and retrieve the contents of the file: ``` curl "http://your-ip:5173/@fs/etc/passwd?raw??" ``` This request will return the contents of the `/etc/passwd` file: ![](2.png) Alternatively, you can also use the `?import&raw??` query parameters to achieve the same result.