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vite/CVE-2025-30208/README.md
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# Vite Development Server Arbitrary File Read Bypass (CVE-2025-30208)
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[中文版本(Chinese version)](README.zh-cn.md)
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Vite is a modern frontend build tool that provides a faster and leaner development experience for modern web projects. It consists of two major parts: a dev server with Hot Module Replacement (HMR) capability, and a build command that bundles your code with Rollup.
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In versions of Vite before 6.2.3, 6.1.2, 6.0.12, 5.4.15, and 4.5.10, the `server.fs.deny` feature, which is designed to restrict access to files outside of Vite's serving allow list, can be bypassed. By appending `?raw??` or `?import&raw??` to URLs using the `@fs` prefix, an attacker can read arbitrary files on the filesystem, as long as the Node.js process has permission to read them.
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This vulnerability occurs because trailing separators such as `?` are removed in several places during request processing, but are not accounted for in query string regular expressions, leading to the security check bypass.
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This vulnerability is a bypass for the patch of [CNVD-2022-44615](../CNVD-2022-44615/README.md).
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References:
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- <https://github.com/vitejs/vite/security/advisories/GHSA-x574-m823-4x7w>
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- <https://nvd.nist.gov/vuln/detail/CVE-2025-30208>
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## Environment Setup
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Execute the following command to start a Vite 6.2.2 development server:
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```
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docker compose up -d
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```
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After the server starts, you can access the Vite development environment at `http://your-ip:5173`.
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> Note: The development server of the old version of Vite defaults to port 3000, while the new version defaults to port 5173, please pay attention to the difference.
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## Vulnerability Reproduction
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The vulnerability allows an attacker to read arbitrary files on the server's filesystem by bypassing the `server.fs.deny` protection.
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First, try to access `/etc/passwd` using the standard `@fs` prefix to verify that normal access to files outside the allowed directories is properly blocked:
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You should receive a 403 Forbidden response because this path is outside of Vite's allowed serving list.
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However, by appending `?raw??` to the URL, you can bypass this restriction and retrieve the contents of the file:
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```
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curl "http://your-ip:5173/@fs/etc/passwd?raw??"
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```
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This request will return the contents of the `/etc/passwd` file:
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Alternatively, you can also use the `?import&raw??` query parameters to achieve the same result.
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