first commit
This commit is contained in:
73
01.基础语法/06.推导式.md
Normal file
73
01.基础语法/06.推导式.md
Normal file
@@ -0,0 +1,73 @@
|
||||
# 推导式
|
||||
|
||||
## 推导式详细格式
|
||||
|
||||
```plain
|
||||
variable = [out_exp_res for out_exp in input_list if out_exp == 2]
|
||||
out_exp_res: 列表生成元素表达式,可以是有返回值的函数。
|
||||
for out_exp in input_list: 迭代input_list将out_exp传入out_exp_res表达式中。
|
||||
if out_exp == 2: 根据条件过滤哪些值可以。
|
||||
```
|
||||
|
||||
## 列表推导式
|
||||
|
||||
30以内所有能被3整除的数
|
||||
|
||||
```python
|
||||
multiples = [i for i in range(30) if i % 3 is 0]
|
||||
print(multiples)
|
||||
```
|
||||
|
||||
30以内所有能被3整除的数的平方
|
||||
|
||||
```python
|
||||
def squared(x):
|
||||
return x*x
|
||||
multiples = [squared(i) for i in range(30) if i % 3 is 0]
|
||||
print(multiples)
|
||||
```
|
||||
|
||||
找到嵌套列表中名字含有两个及以上‘a’的所有名字
|
||||
|
||||
```python
|
||||
fruits = [['peach','Lemon','Pear','avocado','cantaloupe','Banana','Grape'],
|
||||
['raisins','plum','apricot','nectarine','orange','papaya']]
|
||||
print([name for lst in fruits for name in lst if name.count('a') >= 2])
|
||||
```
|
||||
|
||||
## 字典推导式
|
||||
|
||||
将一个字典的key和value对调
|
||||
|
||||
```python
|
||||
dic1 = {'a':1,'b':2}
|
||||
dic2 = {dic1[k]: k for k in dic1}
|
||||
print(dic2)
|
||||
```
|
||||
|
||||
合并大小写对应的value值,将k统一成小写
|
||||
|
||||
```python
|
||||
dic1 = {'a':1,'b':2,'A':4,'Y':9}
|
||||
dic2 = {k.lower():dic1.get(k.lower(),0) + dic1.get(k.upper(),0) for k in dic1.keys()}
|
||||
print(dic2)
|
||||
```
|
||||
|
||||
## 集合推导式
|
||||
|
||||
计算列表中每个值的平方,自带去重功能
|
||||
|
||||
```python
|
||||
l = [1,2,3,4,1,-1,-2,3]
|
||||
squared = {x**2 for x in l}
|
||||
print(squared)
|
||||
```
|
||||
|
||||
## 练习题
|
||||
|
||||
1. 过滤掉长度小于3的字符串列表,并将剩下的转换成大写字母
|
||||
2. 求(x,y)其中x是0-5之间的偶数,y是0-5之间的奇数组成的元祖列表
|
||||
3. 将1000以内的素数放入一个列表中
|
||||
|
||||
|
||||
|
Reference in New Issue
Block a user